To determine if an aspect has been diminished or oxidized, the oxidation number is it was observed in both the reactant and also product phase.

You are watching: Mg(s) + cr(c2h3o2)3(aq)

An rise in oxidation number denotes that the element has to be oxidized.

A to decrease in oxidation number denotes the the element has to be reduced.

Oxidation variety of Mg:

Reactant - 0

Product - +3

Oxidation variety of Cr:

Reactant - +3

Product - 0

Note: C2H3O2 is in reality acetate ion; CH3COO- The oxidatioon number of C, H and also O execute not change.

Oxidized : Mg

Reduced : Cr



Answer from: carmencolon119

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explanation:



Answer from: pedrojulianhdz2005

Cd(s) + AgNO₃(aq) → Cd(NO₃)₂ (aq) + Ag(s)

Oxidized: Cd

Reduced: Ag

Explanation:

Cd(s) + AgNO₃(aq) → Cd(NO₃)₂ (aq) + Ag(s)

Cd → Cd²⁺ + 2e⁻ half reaction oxidation

1e⁻ + Ag⁺ → Ag half reaction reduction

Ag changed oxidation number indigenous +1 to 0

Cd changed oxidation number indigenous 0 come +2

Let"s ballance the electrons

( Cd → Cd²⁺ + 2e⁻ ) .1

( 1e⁻ + Ag⁺ → Ag ) .2

Cd + 2e⁻ + 2Ag⁺ → 2Ag + Cd²⁺ + 2e⁻

Finally the ballance equation is:

Cd(s) + 2AgNO₃(aq) → Cd(NO₃)₂ (aq) + 2Ag(s)


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