The answer is 0.508gramThe molecule mass because that aspirin (C9H8O4) should be 180g/mol. One mol is created of 6.02* 10^23 molecule. So, the massive of 1.70×1021 molecules of aspirin would certainly be: (1.70×10^21 molecules) * (1 mol /6.02* 10^23 molecule) * 180g/mol= 0.508 gram
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is the mass of that aspirin.

You are watching: What is the mass, in grams, of 1.70×1021 molecules of aspirin, c9h8o4?

Further Explanation:

Avogadro’s number is a mathematics number that determines the variety of atoms or molecule in one mole that the substance. The value of Avogadro’s number is

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. This units have the right to either be atom or molecules.

There space

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in one mole that aspirin. As such the number of moles in that aspirin have the right to be calculated as follows:

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The moles of aspirin deserve to be calculate by the following formula.s

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…… (1)

Rearrange equation (1) for the fixed of aspirin.

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…… (2)

The molar fixed of aspirin

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deserve to be calculated as follows:

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" /> …… (3)

Substitute 12.01 g for the atomic mass the C, 1.008 g for the atom mass of H and also 15.99 g because that the atom mass of O in equation (3).

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\&= left< 108.09 ext g + 8.064 ext g + 63.96 ext g ight>\&= 180.114 ext g/mol\endaligned" />

Substitute 0.002823 mol for the moles of aspirin and also 180.114 g/mol because that the molar fixed of aspirin in equation (2).

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Therefore the massive of aspirin is 0.508 g.

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Answer details:

Grade: senior School

Chapter: Mole concept

Subject: Chemistry

Keywords: aspirin, molar mass, atomic mass, C, H, O, C9H8O4, Avogadro’s number, 0.508 g, 15.99 g, 12.01 g, 1.008 g.